yang bisa jawab yahh
r = akar 25 + 144
r = akar 169
r = 13 cm [answer.2.content]
Jawaban:
[tex]dik = a = 5 \: cm \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: t = 12 \: cm[/tex]
[tex]dit = r[/tex]
[tex] \\ penyelesaian = [/tex]
[tex]r = \sqrt{ {a}^{2} + {t}^{2} } [/tex]
[tex]r = \sqrt{ {5}^{2} + {12}^{2} } [/tex]
[tex]r = \sqrt{25 + 144} [/tex]
[tex]r = \sqrt{169} [/tex]
[tex]r = 13 \: cm[/tex]
[tex]semoga \: membantu \: jadikan \\ jawaban \: tercerdas \: yaa[/tex]
r = akar 5^2 + 12^2r = akar 25 + 144
r = akar 169
r = 13 cm [answer.2.content]